Find k for kmeans using the elbow method?
The KMeans algorithm can cluster observed data. But how many clusters (k) are there?
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Determine optimal k
The technique to determine K, the number of clusters, is called the elbow method.
With a bit of fantasy, you can see an elbow in the chart below.
We’ll plot:
- values for K on the horizontal axis
- the distortion on the Y axis (the values calculated with the cost function).
This results in:
When K increases, the centroids are closer to the clusters centroids.
The improvements will decline, at some point rapidly, creating the elbow shape.
That point is the optimal value for K. In the image above, K=3.
Elbow method example
The example code below creates finds the optimal value for k. # clustering dataset
# determine k using elbow method
from sklearn.cluster import KMeans
from sklearn import metrics
from scipy.spatial.distance import cdist
import numpy as np
import matplotlib.pyplot as plt
x1 = np.array([3, 1, 1, 2, 1, 6, 6, 6, 5, 6, 7, 8, 9, 8, 9, 9, 8])
x2 = np.array([5, 4, 5, 6, 5, 8, 6, 7, 6, 7, 1, 2, 1, 2, 3, 2, 3])
plt.plot()
plt.xlim([0, 10])
plt.ylim([0, 10])
plt.title('Dataset')
plt.scatter(x1, x2)
plt.show()
# create new plot and data
plt.plot()
X = np.array(list(zip(x1, x2))).reshape(len(x1), 2)
colors = ['b', 'g', 'r']
markers = ['o', 'v', 's']
# k means determine k
distortions = []
K = range(1,10)
for k in K:
kmeanModel = KMeans(n_clusters=k).fit(X)
kmeanModel.fit(X)
distortions.append(sum(np.min(cdist(X, kmeanModel.cluster_centers_, 'euclidean'), axis=1)) / X.shape[0])
# Plot the elbow
plt.plot(K, distortions, 'bx-')
plt.xlabel('k')
plt.ylabel('Distortion')
plt.title('The Elbow Method showing the optimal k')
plt.show()
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How is the calculated distortion different from kmeanModel.inertia_ ? Thank you!